Bounded set (topological vector space)
In functional analysis and related areas of mathematics, a set in a topological vector space is called bounded or von Neumann bounded, if every neighborhood of the zero vector can be inflated to include the set.
A set that is not bounded is called unbounded.
Bounded sets are a natural way to define locally convex polar topologies on the vector spaces in a dual pair, as the polar set of a bounded set is an absolutely convex and absorbing set.
The concept was first introduced by John von Neumann and Andrey Kolmogorov in 1935.
Definition
Suppose is a topological vector space over a topological fieldA subset of is called ' or just ' in if any of the following equivalent conditions are satisfied:
- : For every neighborhood of the origin there exists a real such that for all scalars satisfying
- This was the definition introduced by John von Neumann in 1935.
- is absorbed by every neighborhood of the origin.
- For every neighborhood of the origin there exists a scalar such that
- For every neighborhood of the origin there exists a real such that for all scalars satisfying
- For every neighborhood of the origin there exists a real such that for all real
- Any one of statements through above but with the word "neighborhood" replaced by any of the following: "balanced neighborhood," "open balanced neighborhood," "closed balanced neighborhood," "open neighborhood," "closed neighborhood".
- e.g. Statement may become: is bounded if and only if is absorbed by every balanced neighborhood of the origin.
- If is locally convex then the adjective "convex" may be also be added to any of these 5 replacements.
- For every sequence of scalars that converges to and every sequence in the sequence converges to in
- This was the definition of "bounded" that Andrey Kolmogorov used in 1934, which is the same as the definition introduced by Stanisław Mazur and Władysław Orlicz in 1933 for metrizable TVS. Kolmogorov used this definition to prove that a TVS is seminormable if and only if it has a bounded convex neighborhood of the origin.
- For every sequence in the sequence converges to in
- Every countable subset of is bounded.
- Any one of statements through above but with the neighborhoods limited to those belonging to
- e.g. Statement may become: For every there exists a scalar such that
- is bounded for all
- There exists a sequence of non-zero scalars such that for every sequence in the sequence is bounded in .
- For all is bounded in the normed space">Normed space">normed space
- B is weakly bounded, i.e. every continuous linear functional is bounded on B
- is a norm bounded subset of By definition, this means that there exists a real number such that for all
- Thus, if is a linear map between two normed spaces and if is the closed unit ball in centered at the origin, then is a bounded linear operator if and only if the image of this ball under is a norm bounded subset of
- is a subset of some ball.
- This ball need not be centered at the origin, but its radius must be positive and finite.
- is contained in the closure of
- In other words, a vector subspace of is bounded if and only if it is a subset of
- Recall that is a Hausdorff space if and only if is closed in So the only bounded vector subspace of a Hausdorff TVS is
Bornology and fundamental systems of bounded sets
The collection of all bounded sets on a topological vector space is called the or theA or of is a set of bounded subsets of such that every bounded subset of is a subset of some
The set of all bounded subsets of trivially forms a fundamental system of bounded sets of
Examples
In any locally convex TVS, the set of closed and bounded disks are a base of bounded set.Examples and sufficient conditions
Unless indicated otherwise, a topological vector space need not be Hausdorff nor locally convex.- Finite sets are bounded.
- Every totally bounded subset of a TVS is bounded.
- Every relatively compact set in a topological vector space is bounded. If the space is equipped with the weak topology the converse is also true.
- The set of points of a Cauchy sequence is bounded, the set of points of a Cauchy net need not be bounded.
- The closure of the origin is always a bounded closed vector subspace. This set is the unique largest bounded vector subspace of In particular, if is a bounded subset of then so is
A set that is not bounded is said to be unbounded.
Any vector subspace of a TVS that is not a contained in the closure of is unbounded
There exists a Fréchet space having a bounded subset and also a dense vector subspace such that is contained in the closure of any bounded subset of
Stability properties
- In any TVS, finite unions, finite Minkowski sums, scalar multiples, translations, subsets, closures, interiors, and balanced hulls of bounded sets are again bounded.
- In any locally convex TVS, the convex hull of a bounded set is again bounded. However, this may be false if the space is not locally convex, as the Lp space spaces for have no nontrivial open convex subsets.
- The image of a bounded set under a continuous linear map is a bounded subset of the codomain.
- A subset of an arbitrary (Cartesian) product of TVSs is bounded if and only if its image under every coordinate projections is bounded.
- If and is a topological vector subspace of then is bounded in if and only if is bounded in
- In other words, a subset is bounded in if and only if it is bounded in every topological vector superspace of
Properties
A locally convex topological vector space has a bounded neighborhood of zero if and only if its topology can be defined by a seminorm.The polar of a bounded set is an absolutely convex and absorbing set.
Using the definition of uniformly bounded sets given below, Mackey's countability condition can be restated as: If are bounded subsets of a metrizable locally convex space then there exists a sequence of positive real numbers such that are uniformly bounded.
In words, given any countable family of bounded sets in a metrizable locally convex space, it is possible to scale each set by its own positive real so that they become [|uniformly bounded].
Generalizations
Uniformly bounded sets
A family of sets of subsets of a topological vector space is said to be in if there exists some bounded subset of such thatwhich happens if and only if its union
is a bounded subset of
In the case of a normed space, a family is uniformly bounded if and only if its union is norm bounded, meaning that there exists some real such that for every or equivalently, if and only if
A set of maps from to is said to be if the family is uniformly bounded in which by definition means that there exists some bounded subset of such that or equivalently, if and only if is a bounded subset of
A set of linear maps between two normed spaces and is uniformly bounded on some open ball in if and only if their operator norms are uniformly bounded; that is, if and only if
Assume is equicontinuous and let be a neighborhood of the origin in
Since is equicontinuous, there exists a neighborhood of the origin in such that for every
Because is bounded in there exists some real such that if then
So for every and every which implies that Thus is bounded in Q.E.D.
Let be a balanced neighborhood of the origin in and let be a closed balanced neighborhood of the origin in such that
Define
which is a closed subset of that satisfies for every
Note that for every non-zero scalar the set is closed in and so every is closed in
It will now be shown that from which follows.
If then being bounded guarantees the existence of some positive integer such that where the linearity of every now implies thus and hence as desired.
Thus
expresses as a countable union of closed sets.
Since is a nonmeager subset of itself, this is only possible if there is some integer such that has non-empty interior in
Let be any point belonging to this open subset of
Let be any balanced open neighborhood of the origin in such that
The sets form an increasing cover of the compact space so there exists some such that .
It will be shown that for every thus demonstrating that is uniformly bounded in and completing the proof.
So fix and
Let
The convexity of guarantees and moreover, since
Thus which is a subset of
Since is balanced and we have which combined with gives
Finally, and imply
as desired. Q.E.D.
Since every singleton subset of is also a bounded subset, it follows that if is an equicontinuous set of continuous linear operators between two topological vector spaces and, then the orbit of every is a bounded subset of
Bounded subsets of topological modules
The definition of bounded sets can be generalized to topological modules.A subset of a topological module over a topological ring is bounded if for any neighborhood of there exists a neighborhood of such that