Ratio test
In mathematics, the ratio test is a test for the convergence of a series
where each term is a real or complex number and is nonzero when is large. The test was first published by Jean le Rond d'Alembert and is sometimes known as d'Alembert's ratio test or as the Cauchy ratio test.
The test
The usual form of the test makes use of the limitThe ratio test states that:
- if L < 1 then the series converges absolutely;
- if L > 1 then the series diverges;
- if L = 1 or the limit fails to exist, then the test is inconclusive, because there exist both convergent and divergent series that satisfy this case.
Then the ratio test states that:
- if R < 1, the series converges absolutely;
- if r > 1, the series diverges; or equivalently if for all large n, the series also diverges; this is because is nonzero and increasing and hence does not approach zero;
- the test is otherwise inconclusive.
Examples
Convergent because ''L'' < 1
Consider the seriesApplying the ratio test, one computes the limit
Since this limit is less than 1, the series converges.
Divergent because ''L'' > 1
Consider the seriesPutting this into the ratio test:
Thus the series diverges.
Inconclusive because ''L'' = 1
Consider the three seriesThe first series diverges, the second converges absolutely and the third converges conditionally. However, the term-by-term magnitude ratios of the three series are and . So, in all three, the limit is equal to 1. This illustrates that when L = 1, the series may converge or diverge: the ratio test is inconclusive. In such cases, more refined tests are required to determine convergence or divergence.
Proof
Below is a proof of the validity of the generalized ratio test.Suppose that. We also suppose that has infinite non-zero members, otherwise the series is just a finite sum hence it converges. Then there exists some such that there exists a natural number satisfying and for all, because if no such exists then there exists arbitrarily large satisfying for every, then we can find a subsequence satisfying, but this contradicts the fact that is the limit inferior of as, implying the existence of. Then we notice that for,. Notice that so as and, this implies diverges so the series diverges by the n-th term test.
Now suppose. Similar to the above case, we may find a natural number and a such that for. Then
The series is the geometric series with common ratio, hence which is finite. The sum is a finite sum and hence it is bounded, this implies the series converges by the monotone convergence theorem and the series converges by the absolute convergence test.
When the limit exists and equals to then, this gives the original ratio test.
Extensions for ''L'' = 1
As seen in the previous example, the ratio test may be inconclusive when the limit of the ratio is 1. Extensions to the ratio test, however, sometimes allow one to deal with this case.In all the tests below one assumes that Σan is a sum with positive an. These tests also may be applied to any series with a finite number of negative terms. Any such series may be written as:
where aN is the highest-indexed negative term. The first expression on the right is a partial sum which will be finite, and so the convergence of the entire series will be determined by the convergence properties of the second expression on the right, which may be re-indexed to form a series of all positive terms beginning at n=1.
Each test defines a test parameter which specifies the behavior of that parameter needed to establish convergence or divergence. For each test, a weaker form of the test exists which will instead place restrictions upon limn->∞ρn.
All of the tests have regions in which they fail to describe the convergence properties of Σan. In fact, no convergence test can fully describe the convergence properties of the series. This is because if Σan is convergent, a second convergent series Σbn can be found which converges more slowly: i.e., it has the property that limn->∞ = ∞. Furthermore, if Σan is divergent, a second divergent series Σbn can be found which diverges more slowly: i.e., it has the property that limn->∞ = 0. Convergence tests essentially use the comparison test on some particular family of an, and fail for sequences which converge or diverge more slowly.
De Morgan hierarchy
proposed a hierarchy of ratio-type testsThe ratio test parameters below all generally involve terms of the form. This term may be multiplied by to yield. This term can replace the former term in the definition of the test parameters and the conclusions drawn will remain the same. Accordingly, there will be no distinction drawn between references which use one or the other form of the test parameter.
1. d'Alembert's ratio test
The first test in the De Morgan hierarchy is the ratio test as described above.2. Raabe's test
This extension is due to Joseph Ludwig Raabe. Define:The series will:
- Converge when there exists a c>1 such that for all n>N.
- Diverge when for all n>N.
- Otherwise, the test is inconclusive.
- Converge if
- Diverge if.
- If ρ = 1, the test is inconclusive.
- Converge if
- Diverge if
- Otherwise, the test is inconclusive.
Proof of Raabe's test
The proof proceeds essentially by comparison with. Suppose first that. Of course
if then for large, so the sum diverges; assume then that. There exists such that for all, which is to say that. Thus, which implies that
for ; since this shows that diverges.
The proof of the other half is entirely analogous, with most of the inequalities simply reversed. We need a preliminary inequality to use
in place of the simple that was used above: Fix and. Note that
. So ; hence.
Suppose now that. Arguing as in the first paragraph, using the inequality established in the previous paragraph, we see that there exists such that for ; since this shows that converges.
3. Bertrand's test
This extension is due to Joseph Bertrand and Augustus De Morgan.Defining:
Bertrand's test asserts that the series will:
- Converge when there exists a c>1 such that for all n>N.
- Diverge when for all n>N.
- Otherwise, the test is inconclusive.
- Converge if
- Diverge if.
- If ρ = 1, the test is inconclusive.
- Converge if
- Diverge if
- Otherwise, the test is inconclusive.
4. Extended Bertrand's test
Let be an integer, and let denote the th iterate of natural logarithm, i.e. and for any,
Suppose that the ratio, when is large, can be presented in the form
The value can be presented explicitly in the form
Extended Bertrand's test asserts that the series
- Converge when there exists a such that for all.
- Diverge when for all.
- Otherwise, the test is inconclusive.
- Converge if
- Diverge if.
- If, the test is inconclusive.
- Converge if
- Diverge if
- Otherwise, the test is inconclusive.
5. Gauss's test
This extension is due to Carl Friedrich Gauss.Assuming an > 0 and r > 1, if a bounded sequence Cn can be found such that for all n:
then the series will:
- Converge if
- Diverge if
6. Kummer's test
Let ζn be an auxiliary sequence of positive constants. Define
Kummer's test states that the series will:
- Converge if there exists a such that for all n>N.
- Diverge if for all n>N and diverges.
- Converge if
- Diverge if and diverges.
- Otherwise the test is inconclusive
- Converge if
- Diverge if and diverges.
Special cases
- For the ratio test, let ζn=1. Then:
- For Raabe's test, let ζn=n. Then:
- For Bertrand's test, let ζn=n ln. Then:
- For Extended Bertrand's test, let From the Taylor series expansion for large we arrive at the approximation
Hence,
Note that for these four tests, the higher they are in the De Morgan hierarchy, the more slowly the series diverges.
Proof of Kummer's test
If then fix a positive number. There existsa natural number such that for every
Since, for every
In particular for all which means that starting from the index
the sequence is monotonically decreasing and
positive which in particular implies that it is bounded below by 0. Therefore, the limit
This implies that the positive telescoping series
and since for all
by the direct comparison test for positive series, the series
is convergent.
On the other hand, if, then there is an N such that is increasing for. In particular, there exists an for which for all, and so diverges by comparison with.
Tong's modification of Kummer's test
A new version of Kummer's test was established by Tong. See alsofor further discussions and new proofs. The provided modification of Kummer's theorem characterizes
all positive series, and the convergence or divergence can be formulated in the form of two necessary and sufficient conditions, one for convergence and another for divergence.
- Series converges if and only if there exists a positive sequence,, such that
- Series diverges if and only if there exists a positive sequence,, such that and
- Series converges if and only if there exists a positive sequence,, such that
- Series diverges if and only if there exists a positive sequence,, such that and
Frink's ratio test
Another ratio test that can be set in the framework of Kummer's theorem was presented by Orrin Frink 1948.Suppose is a sequence in,
- If, then the series converges absolutely.
- If there is such that for all, then diverges.
Ali's second ratio test
A more refined ratio test is the second ratio test:For define:
By the second ratio test, the series will:
- Converge if
- Diverge if
- If then the test is inconclusive.
Then the series will:
- Converge if
- Diverge if
- If then the test is inconclusive.
Ali's ''m''th ratio test
By the th ratio test, the series will:
- Converge if
- Diverge if
- If then the test is inconclusive.
Then the series will:
- Converge if
- Diverge if
- If, then the test is inconclusive.
Ali--Deutsche Cohen φ-ratio test
Assume that the sequence is a positive decreasing sequence.
Let be such that exists. Denote, and assume.
Assume also that
Then the series will:
- Converge if
- Diverge if
- If, then the test is inconclusive.