2019 China Open (snooker)


The 2019 XingPai China Open was a professional ranking snooker tournament, that took place between 1–7 April 2019 in Beijing, China. It was the nineteenth and penultimate ranking event of the 2018/2019 season.
Neil Robertson won his second China Open title, and the 16th ranking title of his career, defeating Jack Lisowski 11–4 in the final.
Mark Selby was the two-time reigning champion, having defended his 2017 title with an 11–3 win against Barry Hawkins in the 2018 final. However, he lost 3–6 to Craig Steadman in qualifying.
Stuart Bingham made the highest break of the event, with his fifth 147 break of his career in his second round match with Peter Ebdon. It was the 151st 147 in snooker history.

Prize fund

The breakdown of prize money is shown below.
  • Winner: £225,000
  • Runner-up: £90,000
  • Semi-final: £45,000
  • Quarter-final: £27,000
  • Last 16: £18,000
  • Last 32: £11,000
  • Last 64: £5,000
  • Televised highest break: £7,000
  • Total: £1,000,000
The "rolling 147 prize" for a maximum break: £20,000

Qualifying

Qualifying – excluding held over matches – took place between 18 and 20 February 2019 at the Chase Leisure Centre in Cannock, England.
All qualifying matches were best of 11 frames.
;Note

Century breaks

Main stage centuries

Total: 78 11 of these centuries were made in held over matches, by Ding Junhui, Xiao Guodong, Mark King, Harvey Chandler, Wu Yize, Soheil Vahedi, Craig Steadman and Mark Williams.

Qualifying stage centuries

Total: 35