1960 NBA playoffs


The 1960 NBA playoffs was the postseason tournament of the National Basketball Association's 1959–60 season. The tournament concluded with the Eastern Division champion Boston Celtics defeating the Western Division champion St. Louis Hawks 4 games to 3 in the NBA Finals.
This was the second straight and third overall NBA title for Boston, who got revenge for the Hawks' win over them in 1958. The 1960 Finals was the third Celtics–Hawks Finals in the past four years.

Division Semifinals

Eastern Division Semifinals

(2) [Philadelphia Warriors] vs. (3) [Syracuse Nationals]

This was the seventh playoff meeting between these two teams, with the 76ers/Nationals winning four of the first six meetings.
Philadelphia 76ers/ Syracuse Nationals leads 4–2 in all-time playoff series


Western Division Semifinals

(2) [Detroit Pistons] vs. (3) [Minneapolis Lakers]

This was the seventh playoff meeting between these two teams, with the Lakers winning five of the first six meetings.
Minneapolis leads 5–1 in all-time playoff series


Division Finals

Eastern Division Finals

(1) [Boston Celtics] vs. (2) [Philadelphia Warriors]

This was the second playoff meeting between these two teams, with the Celtics winning the first meeting.
Boston leads 1–0 in all-time playoff series


Western Division Finals

(1) [St. Louis Hawks] vs. (3) [Minneapolis Lakers]

This was the fourth playoff meeting between these two teams, with the Hawks winning two of the first three meetings.
St. Louis leads 2–1 in all-time playoff series


NBA Finals: (E1) Boston Celtics vs. (W1) St. Louis Hawks

This was the third playoff meeting between these two teams, with both teams splitting the first two meetings.
Tied 1–1 in all-time playoff series