1956 Iowa Senate election
The 1956 Iowa State Senate elections took place as part of the biennial 1956 United States elections. Iowa voters elected state senators in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.
A statewide map of the 50 state Senate districts in the year 1956 is provided by the Iowa General Assembly
The primary election on June 4, 1956, determined which candidates appeared on the November 6, 1956 general election ballot.
Following the previous election, Republicans had control of the Iowa state Senate with 44 seats to Democrats' 6 seats.
To claim control of the chamber from Republicans, the Democrats needed to net 20 Senate seats.
Republicans maintained control of the Iowa State Senate following the 1956 general election with the balance of power shifting to Republicans holding 40 seats and Democrats having 10 seats.
Summary of Results
- Note: The 21 holdover Senators not up for re-election are not listed on this table.
Detailed Results
- NOTE: The 21 districts that did not hold elections in 1956 are not listed here.
[|District 2] • [|District 3] • [|District 4] • [|District 5] • [|District 6] • [|District 8] • [|District 11] • [|District 14] • [|District 15] • [|District 16] • [|District 17] • [|District 19] • [|District 23] • [|District 24] • [|District 25] • [|District 26] • [|District 27] • [|District 28] • [|District 31] • [|District 32] • [|District 33] • [|District 36] • [|District 39] • [|District 40] • [|District 41] • [|District 43] • [|District 46] • [|District 47] • [|District 49] |
- Note: The Iowa Secretary of State's website does not document any competitive intra-party primaries for state Senate races in 1956.