1890 Belgian general election


Partial general elections were held in Belgium on 10 June 1890. In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.

Constituencies

The distribution of seats among the electoral districts was as follows:
ProvinceArrondissementSeats
AntwerpAntwerp8
AntwerpMechelen3
AntwerpTurnhout3
LimburgHasselt2
LimburgMaaseik1
LimburgTongeren2
East FlandersAalst4
East FlandersOudenaarde3
East FlandersGent8
East FlandersEeklo1
East FlandersDendermonde3
East FlandersSint-Niklaas3
West FlandersBruges3
West FlandersRoeselare2
West FlandersTielt2
West FlandersKortrijk4
West FlandersYpres3
West FlandersVeurne1
West FlandersDiksmuide1
West FlandersOstend1
BrabantLeuven5
BrabantBrussels16
BrabantNivelles4
HainautTournai4
HainautAth2
HainautCharleroi7
HainautThuin3
HainautMons6
HainautSoignies3
LiègeHuy2
LiègeWaremme2
LiègeLiège9
LiègeVerviers4
LuxembourgArlon1
LuxembourgMarche1
LuxembourgBastogne1
LuxembourgNeufchâteau1
LuxembourgVirton1
NamurNamur4
NamurDinant2
NamurPhilippeville2