Jacobson density theorem
In mathematics, more specifically non-commutative ring theory, modern algebra, and module theory, the Jacobson density theorem is a theorem concerning simple modules over a ring.
The theorem can be applied to show that any primitive ring can be viewed as a "dense" subring of the ring of linear transformations of a vector space. This theorem first appeared in the literature in 1945, in the famous paper "Structure Theory of Simple Rings Without Finiteness Assumptions" by Nathan Jacobson. This can be viewed as a kind of generalization of the Artin-Wedderburn theorem's conclusion about the structure of simple Artinian rings.
Motivation and formal statement
Let be a ring and let be a simple right -module. If is a non-zero element of, . Therefore, if are non-zero elements of, there is an element of that induces an endomorphism of transforming to. The natural question now is whether this can be generalized to arbitrary tuples of elements. More precisely, find necessary and sufficient conditions on the tuple and separately, so that there is an element of with the property that for all. If is the set of all -module endomorphisms of, then Schur's lemma asserts that is a division ring, and the Jacobson density theorem answers the question on tuples in the affirmative, provided that the are linearly independent over.With the above in mind, the theorem may be stated this way:
Proof
In the Jacobson density theorem, the right -module is simultaneously viewed as a left -module where, in the natural way:. It can be verified that this is indeed a left module structure on. As noted before, Schur's lemma proves is a division ring if is simple, and so is a vector space over.The proof also relies on the following theorem proven in p. 185:
Proof of the Jacobson density theorem
We use induction on. If is empty, then the theorem is vacuously true and the base case for induction is verified.Assume is non-empty, let be an element of and write If is any -linear transformation on, by the induction hypothesis there exists such that for all in. Write. It is easily seen that is a submodule of. If, then the previous theorem implies that would be in the -span of, contradicting the -linear independence of, therefore. Since is simple, we have:. Since, there exists in such that.
Define and observe that for all in we have:
Now we do the same calculation for :
Therefore, for all in, as desired. This completes the inductive step of the proof. It follows now from mathematical induction that the theorem is true for finite sets of any size.