Least-upper-bound property
In mathematics, the least-upper-bound property is a fundamental property of the real numbers. More generally, a partially ordered set has the least-upper-bound property if every non-empty subset of with an upper bound has a least upper bound in. Not every ordered set has the least upper bound property. For example, the set of all rational numbers with its natural order does not have the least upper bound property.
The least-upper-bound property is one form of the completeness axiom for the real numbers, and is sometimes referred to as Dedekind completeness. It can be used to prove many of the fundamental results of real analysis, such as the intermediate value theorem, the Bolzano–Weierstrass theorem, the extreme value theorem, and the Heine–Borel theorem. It is usually taken as an axiom in synthetic constructions of the real numbers, and it is also intimately related to the construction of the real numbers using Dedekind cuts.
In order theory, this property can be generalized to a notion of completeness for any partially ordered set. A linearly ordered set that is dense and has the least upper bound property is called a linear continuum.
Statement of the property
Statement for real numbers
Let be a non-empty set of real numbers.- A real number is called an upper bound for if for all.
- A real number is the least upper bound for if is an upper bound for and for every upper bound of.
Generalization to ordered sets
More generally, one may define upper bound and least upper bound for any subset of a partially ordered set, with “real number” replaced by “element of ”. In this case, we say that has the least-upper-bound property if every non-empty subset of with an upper bound has a least upper bound in .For example, the set of rational numbers does not have the least-upper-bound property under the usual order. For instance, the set
has an upper bound in, but does not have a least upper bound in . The construction of the real numbers using Dedekind cuts takes advantage of this failure by defining the irrational numbers as the least upper bounds of certain subsets of the rationals.
Proof
Logical status
The least-upper-bound property is equivalent to other forms of the completeness axiom, such as the convergence of Cauchy sequences or the nested intervals theorem. The logical status of the property depends on the construction of the real numbers used: in the synthetic approach, the property is usually taken as an axiom for the real numbers; in a constructive approach, the property must be proved as a theorem, either directly from the construction or as a consequence of some other form of completeness.Proof using Cauchy sequences
It is possible to prove the least-upper-bound property using the assumption that every Cauchy sequence of real numbers converges. Let be a nonempty set of real numbers. If has exactly one element, then its only element is a least upper bound. So consider with more than one element, and suppose that has an upper bound. Since is nonempty and has more than one element, there exists a real number that is not an upper bound for. Define sequences and recursively as follows:- Check whether is an upper bound for.
- If it is, let and let.
- Otherwise there must be an element in so that. Let and let.
Applications
The least-upper-bound property of can be used to prove many of the main foundational theorems in real analysis.Intermediate value theorem
Let be a continuous function, and suppose that and. In this case, the intermediate value theorem states that must have a root in the interval. This theorem can be proved by considering the setThat is, is the initial segment of that takes negative values under. Then is an upper bound for, and the least upper bound must be a root of.
Bolzano–Weierstrass theorem
The Bolzano–Weierstrass theorem for states that every sequence of real numbers in a closed interval must have a convergent subsequence. This theorem can be proved by considering the setClearly,
, and is not empty.
In addition, is an upper bound for, so has a least upper bound.
Then must be a limit point of the sequence, and it follows that has a subsequence that converges to.
Extreme value theorem
Let be a continuous function and let, where if has no upper bound. The extreme value theorem states that is finite and for some. This can be proved by considering the setBy definition of,, and by its own definition, is bounded by.
If is the least upper bound of, then it follows from continuity that.
Heine–Borel theorem
Let be a closed interval in, and let be a collection of open sets that covers. Then the Heine–Borel theorem states that some finite subcollection of covers as well. This statement can be proved by considering the setThe set obviously contains, and is bounded by by construction.
By the least-upper-bound property, has a least upper bound.
Hence, is itself an element of some open set, and it follows for that can be covered by finitely many for some sufficiently small.
This proves that and is not an upper bound for.
Consequently,.